Home & workshop Electronics

Voltage divider calculator

Input voltage
V
R1 (top)
Ω
R2 (bottom)
Ω
Target output
V
Shows the R2 that would give this
Output voltage 6 V
Vout = Vin × R2 ÷ (R1 + R2)
R2 for the target voltage 3,793.1 Ω
Quiescent current 0.6 mA
Total resistance 20,000 Ω
Power in R1 3.6 mW
Power in R2 3.6 mW
Vout = Vin · R2/(R1+R2) · unloaded

The output above assumes nothing is connected to it. The moment a load draws current, it sits in parallel with R2 and the output sags. The rule of thumb is that the divider current should be at least ten times the load current — so a divider feeding a 1 mA load wants at least 10 mA flowing through it, which for a 12 V supply means a total resistance of about 1.2 kΩ and 120 mW burnt continuously. For anything drawing real current, use a regulator.

Advertisement
320 × 100

A voltage divider outputs Vin × R2 ÷ (R1 + R2). Two equal 10 kΩ resistors on 12 V give 6 V at 0.6 mA. The output only holds if the load draws far less current than the divider itself — a factor of ten is the usual minimum.

How to design a voltage divider

1 Enter the input voltage and both resistor values.
2 Read the unloaded output voltage.
3 Enter a target voltage to see the R2 that would produce it.
4 Check the quiescent current is at least ten times whatever the output will feed.

Dividers are for sensing, not for supplying. Scaling a battery voltage down into an ADC input is the textbook use, and it works because an ADC input draws almost nothing. Choosing the values is a trade: high resistances waste less power but are more susceptible to noise and to the input impedance of whatever is reading them; low resistances are stiffer but burn current continuously, which matters enormously in a battery device. For an ADC divider, tens of kilohms is the usual compromise.

Questions

Vout = Vin × R2 ÷ (R1 + R2), where R2 is the resistor between the output and ground.

Advertisement
300 × 250
Was this tool any good?
INTERNAL SIGNAL ONLY · WE USE IT TO FIND TOOLS WORTH REBUILDING