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Resistors in parallel

Arrangement
The two values in ohms
Applied voltage
V
Combined resistance 5,000 Ω
R = R₁R₂ ÷ (R₁ + R₂)
In kilohms 5 kΩ
Total current 2.4 mA
Total dissipation 0.0288 W
Same pair in series 20,000 Ω
Product over sum
WantedPairActualError
500 Ω1 kΩ ∥ 1 kΩ500 Ωexact
750 Ω1 kΩ ∥ 3.3 kΩ767 Ω+2.2%
1.5 kΩ2.2 kΩ ∥ 4.7 kΩ1.50 kΩ+0.0%
2 kΩ3.3 kΩ ∥ 5.6 kΩ2.08 kΩ+3.8%
5 kΩ10 kΩ ∥ 10 kΩ5 kΩexact
8 kΩ10 kΩ ∥ 39 kΩ7.96 kΩ−0.5%
15 kΩ22 kΩ ∥ 47 kΩ15.0 kΩ+0.0%
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Two resistors in parallel give R₁R₂ ÷ (R₁ + R₂). Two 10 kΩ resistors make 5 kΩ exactly. Pairing is the standard workshop trick for hitting a value between the E12 steps you actually have in the drawer.

How to pair resistors

1 Enter two values you actually own.
2 Read the combined resistance.
3 Check the table below for common target values and the pairs that hit them.
4 Verify the dissipation in the smaller resistor is within its rating.

Equal resistors halve, which covers the easy cases. The interesting pairs are the ones that land almost exactly on a value between standard steps: 2.2 kΩ with 4.7 kΩ gives 1.499 kΩ, which is closer to 1.5 kΩ than a 5% 1.5 kΩ resistor is guaranteed to be. That is worth knowing when a design needs a value precisely and only the common series is to hand. It is also a reminder that tolerance dominates: two 5% parts in parallel give a result with roughly 5% uncertainty, so a precise pairing on paper still needs 1% parts to mean anything.

Questions

2.2 kΩ in parallel with 4.7 kΩ gives 1.499 kΩ — closer than a 5% 1.5 kΩ part is guaranteed to be.

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