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Capacitors in series

Arrangement
Capacitance in microfarads
Total capacitance 5 µF
1/C = 1/C₁ + 1/C₂ + …
In nanofarads 5,000 nF
Same set in parallel 20 µF
Capacitors 2
In farads 0.000005 F
1/C = Σ 1/Cₙ · balance the string
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Capacitors in series follow a reciprocal sum: 1/C = 1/C₁ + 1/C₂ + … Two 10 µF capacitors in series give 5 µF. The total is always smaller than the smallest, and the voltage rating of the string adds up.

How to combine capacitors in series

1 Enter each capacitance.
2 Read the total, which will be below the smallest value.
3 Remember voltage divides across them — but only if they are balanced.
4 Use balancing resistors across each capacitor if the string handles real voltage.

Series is how you get a higher voltage rating than any single capacitor offers, and it comes with a trap. The voltage only divides evenly if the capacitors are matched and their leakage currents are similar. In practice leakage differs, the string drifts, and one capacitor ends up carrying more than its share until it fails — which then puts the full voltage across the next one. Any series string handling significant voltage needs balancing resistors across each capacitor to hold the division steady, which is why you see them on every high-voltage capacitor bank.

Questions

1/C_total = 1/C₁ + 1/C₂ + … For two, C = C₁C₂ ÷ (C₁ + C₂).

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