Fun Acoustics

dB calculator

Mode
Decibels
dB
Voltage ratio 1.99526×
10^(6/20) for voltage, 10^(6/10) for power
Power ratio 3.98107×
As a percentage 199.53 %
Perceived loudness change 1.516×
3 dB doubles power · 6 dB doubles voltage

Three decibels doubles power. Six decibels doubles voltage or amplitude. Ten decibels roughly doubles perceived loudness. All three are correct and they measure different things, which is why "twice as loud" is such a slippery phrase. A 3 dB increase doubles the amplifier work and is barely noticeable, while 10 dB sounds twice as loud and takes ten times the power.

Decibels are logarithmic: 20·log₁₀ of a voltage ratio, or 10·log₁₀ of a power ratio. Six decibels doubles voltage, three doubles power, and ten roughly doubles perceived loudness. Two equal sources sum to 3 dB more, not double, and a point source loses 6 dB per doubling of distance.

How to work with decibels

1 Pick the mode: converting a dB figure, measuring gain, adding two sources, or level over distance.
2 For gain, say whether your levels are voltage or power: the formula differs by a factor of two.
3 For summing, remember two equal sources add just 3 dB.
4 For distance, enter the level at a known reference distance and the range you care about.

Adding decibels is where intuition fails hardest. Two 80 dB speakers together produce 83 dB, not 160. Ten of them produce 90. The reason is that decibels are a logarithmic ratio, so combining sources multiplies the underlying energy and not the dB figure. It also means quiet sources contribute almost nothing next to loud ones; an 80 dB and a 60 dB source together are 80.04 dB, which is why a single loud machine dominates a noise measurement completely.

Gain, and why the formula has two versions

Gain is the ratio between an output and an input expressed in decibels: 20·log₁₀ for voltage or amplitude, 10·log₁₀ for power. Going from 0.1 V to 2 V is 26 dB, which is about twenty times the voltage and four hundred times the power, the same physical change described by two different numbers depending on which quantity you name. The reason for the two versions is that power goes with the square of voltage, and squaring becomes a factor of two once it is inside a logarithm. Say which one your figures are and the rest follows; guess, and you are out by exactly double.

Level over distance

A point source in free space loses 6 dB for every doubling of distance, which is the inverse square law written in decibels. What matters is the ratio of the distances, not the change in metres: moving a microphone from 10 cm to 20 cm halves the level, while moving it from 2 m to 2.1 m barely registers. That is the whole of close-miking technique in one line, and it is also why a source 8 m away is 18 dB down on the same source at 1 m.

The rule is optimistic indoors and pessimistic outdoors. In a room, reflections keep the level up, and beyond the critical distance the reverberant field dominates and the level stops falling at all. Outdoors over absorbing ground (grass, snow, ploughed earth) the loss is steeper than 6 dB per doubling, so a noise assessment built on the free-field figure alone is an estimate and not a measurement.

What people use it for

  • Working out amplifier headroom
  • Adding noise sources for an assessment
  • Understanding a gain specification
  • Converting between dB and a ratio
  • Specifying the gain of a preamp or an amplifier
  • Estimating a sound level at a site boundary
  • Working out microphone placement

Questions

A doubling of power, or about 1.41 times the voltage. It is a small but audible change.

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